A first grader knows that the probability of flipping heads on a coin is 50%. With 3 flips, you have a decent (1/8) chance of all heads, but as the number of flips increases towards infinity, so does the flip average towards 50%. Consequently, infinite heads becomes infinitely impossible.
At first thought, you might suppose 50.0000->% of the total flips landing on heads now means that the quantities of heads and tails become increasingly identical. Quite the contrary: With nearly infinite flips, quinitillions more heads than tails becomes a negligible surplus of increasingly minute proportions. The point being, as the average converges towards 50%, the total numeric tally skews wildly, and in great proportions.
If the same number of flips are repeated, we are just as likely to incur quintillions more tails. What happens is as the coin is flipped infinitely, the total tally skews distantly towards one outcome, and then, eventually (but at random), swings back to the other. The, perhaps, surprising outcome is an infinite cycling. All of this occurs as the total outcome average approaches exactly 50%.
Now let’s suppose you’re drunk, live in a one dimensional world (a straight line), and decide to flip a coin infinitely. Heads means one step the right, and tails one to the left. With infinite flips, it turns out that you will cross every point you’ve already stepped on an infinite number of times! Given infinite time, every event (position) will occur infinite times! What are the philosophical implications of this?
Lets try this experiment again, but in two dimensions. You’re drunk at the bar, but this time decide to walk home, taking steps equally randomly in the cardinal directions. The math ends up working out the same as it does in one dimension. Given infinite repetitions, you’ll cross every point you already stepped on an infinite number of times. You’ll find your home an infinite number of times!
Philosophically speaking, does this mean that in a hypothetical reality of infinite time, we’d end up repeating each action an infinite number of times? Sounds tiring, if not downright miserable or worse. Don’t forget, though, that you will infinitely push your boundaries in one or two dimensions and reach infinite new places as the infinite flips go on. And this is a profound truth alone: the infinite provides for infinite experiences.
The only downside to this reality seems to be having to repeat the experience of each experienced position infinite times! If, for example, one of those points contains an angry panda who wants to bite you every time you cross its path, you’re going to have to endure a vicious panda bite infinite times! So, is there any way to avoid repeating an event that’s blocking your path? Turns out there is.. welcome to the third dimension.
What makes the third dimension different from a one and two dimensional world is the existence of infinite planes. If the panda is located at the X,Y,Z position (10,20,5), you can get around the panda on a different plane, such as (10,20,4.999). If you’re not familiar with Z coordinates, just imagine jumping over the panda or floating underneath it. Obstacle avoided. Consequently, a lost bird traveling at random can fly around infinitely and never find its nest.
Hopefully, the bird didn’t leave anything sentimental in there, but more importantly, this immortal bird has plenty of time to craft a much better nest. So if there does exist a heaven which spans the infinity in more than two dimensions, take comfort in knowing that you may never have to repeat an unpleasant event twice. Likewise, don’t discount a beautiful moment in time. You may never experience that feeling again.

why 660?
“Obstacle evasion” is possible in two or more dimensions, not three or more.
What if the same infinite cycle could go on in the third dimension, in the third coordinate too?
Let’s suppose I’m drunk (:D), and I can levitate. I wanna go home, and move/fly in an equally random direction of X, Y and Z, acconding to the result of the flip (let’s just ignore the fact that it has only two sides, and two possible outcomes. Let’s suppose there’s an infinite number of outcomes.)
So in infinite time, I will end up being infinitely at every friggin’ point of the three-dimensional space, thus I will find my home infinite times, and the panda will bite me infinite times too.
However. As in the 3D version, you have the option of evading in 2D too. Like, I see the pande there (in 2D), so I won’t cross its way, I”ll just get arounf it and it won’t bite me. And if I note the location of the panda every time while infinitely getting into sight, I can evade the panda infinite times. The same applies to the three dimensions.
I find your site especially interesting, I’m glad I found it.
Why 660 ?
Oldie: “Obstacle evasion” is possible in two dimensions if it’s deliberate, the random walk is based only on randomness.
Chaser: Thanks for the comment!
“So in infinite time [given randomness], I will end up being infinitely at every friggin’ point of the three-dimensional space, thus I will find my home infinite times, and the panda will bite me infinite times too.”
Nope
You will revisit your home an indeterminable number of times (0 -> ?). You don’t necessarily ever have to touch the same coordinate again due to there being infinite values being between a real number range like 0 and 1; 0.5, 0.6, 0.55, 0.555, etc. are all different values. If x is 1.0, you could spend an infinite amount of time infinitely dividing x by two, and never ever see the number 0.6.
Yes, if deliberate, you even can evade an obstacle in one dimension I suppose: just go only one direction
660 because I bought the name a decade ago and figured it was time I did something with it!
Hmmm. Interesting
I thought this because I believe that “infinite time” is enough time to visit all the infinite points of infinite space infinite times. But now what you said, brought me thinking:
Let’s say I need a given quantity of time to visit one exact coordinate. So if I divide intinite [amount of time] by infinite [amount of coordinate], I’ll get.. I guess I’ll get 1 as result. So you’re right, I can visit every coordinate only once, if moving deliberately.
So, to visit every coordinate of infinite space infinite times, I’ll need “infinity x infinity” amount of time..? Is that even possible to calculate the power of infinite?
Yes, that’s exactly correct.
Yes, again. There are multiple levels of infinity, this is a good read I found on it:
http://www.xamuel.com/the-higher-infinite/